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Consider a continuously infinite dimensional Hilbert space, i.e. it has a basis $\ket{\chi_k}$ labelled by a continuous index $k$. We call such a basis orthonormal if \[\braket{\chi_{k'}}{\chi_k} = \delta(k-k').\]

Note that this means that \[\braket{\chi_k}{\chi_k} = \delta(0),\] and by the integral representation of the Dirac delta function this is \[\delta(0) = \frac{1}{2\pi}\int_{-\infty}^{+\infty}\D k\, e^{i0} = \frac{1}{2\pi}\int_{-\infty}^{+\infty}\D k\,=\infty,\] so, unlike in the discrete case, the basis vectors are not normalized, $\|\chi_k\| \neq 1$. Since their norms are actually infinite, we cannot normalize them by dividing by a constant either. It is just a fact that there are no normalized continuous bases, so we adopt this convention for orthonormality instead.

The completeness condition (Dirac notaty) in a continuous basis becomes \[\hat{I} = \int_{-\infty}^{+\infty} \D k \, \proj{\chi_k},\] and we can use this to expand any ket $\ket{\psi}$ in the $\ket{\chi_k}$ basis as \[\ket{\psi} = \hat{I}\ket{\psi} = \int_{-\infty}^{+\infty} \D k\,\ket{\chi_k}\braket{\chi_k}{\psi} = \int_{-\infty}^{+\infty}\D \k\, f(k)\ket{\chi_k},\] where $f(k) = \braket{\chi_k}{\psi}$ are the components of $\ket{\psi}$ in the $\ket{\chi_k}$ basis, with the main difference to what we have seen before being that $f(k)$ is now a function of a continuous variable rather than a discrete set of components. We can think of it as a “column vector” with a continuous index.

As in the discrete case, we can similarly represent a bra in a particular basis using the Dirac notaty: \begin{align*} \bra{\psi} & = \bra{\psi}\hat{I} \\ & = \int_{-\infty}^{+\infty} \D k\,\braket{\psi}{\chi_k}\bra{\chi_k} \\ & = \int_{-\infty}^{+\infty} \D k\,\braket{\chi_k}{\psi}^*\bra{\chi_k} \\ & = \int_{-\infty}^{+\infty}\D \k\, f(k)^*\bra{\chi_k}, \end{align*} where we can think of $f^*(k)$ as the components of a “row vector” with a continuous index.

As another example, we can calculate an inner product in a particular basis via: \begin{align*} \braket{\phi}{\psi} & = \sand{\phi}{\hat{I}}{\psi} \\ & = \int_{-\infty}^{+\infty} \D k\, \braket{\phi}{\chi_k} \braket{\chi_k}{\psi} \\ & = \int_{-\infty}^{+\infty} \D k\, \braket{\chi_k}{\phi}^* \braket{\chi_k}{\psi} \\ & = \int_{-\infty}^{+\infty} \D k\, g^*(k) f(k), \end{align*} where $g(k)$ are the components of $\ket{\phi}$ in the $\ket{\chi_k}$ basis, i.e. $\ket{\phi} = \int_{-\infty}^{+\infty} \D k\, g(k) \ket{\chi_k}$.

Finally, we can represent an operator in the $\ket{\chi_k}$ basis via: \begin{align*} \hat{A} & = \hat{I}\hat{A}\hat{I} \\ & = \int_{-\infty}^{+\infty} \D k\, \int_{-\infty}^{+\infty} \D k'\, \ket{\chi_k}\sand{\chi_k}{\hat{A}}{\chi_{k'}} \bra{\chi_{k'}} \\ & = \int_{-\infty}^{+\infty} \D k\, \int_{-\infty}^{+\infty} \D k'\, \sand{\chi_k}{\hat{A}}{\chi_{k'}} \ketbra{\chi_k}{\chi_{k'}} \\ & = \int_{-\infty}^{+\infty} \D k\, \int_{-\infty}^{+\infty} \D k'\, A_{kk'} \ketbra{\chi_k}{\chi_{k'}}, \end{align*} where we think of $A_{kk'} = \sand{\chi_k}{\hat{A}}{\chi_{k'}}$ as the components of a “matrix” with a continuous infinity of rows and columns.

2.vi.1 The Position Representation

Just as in the discrete case, there are an infinite number of orthonormal bases that we could use. However, for most calculations, it is convenient to use just two: the position basis and the momentum basis.